Linear independence Guide, Meaning , Facts, Information and Description
In linear algebra, a set of elements of a vector space is linearly independent if none of the vectorss in the set can be written as a linear combination of finitely many other vectors in the set. For instance, in three-dimensional Euclidean space R3, the three vectors (1, 0, 0), (0, 1, 0) and (0, 0, 1) are linearly independent, while (2, −1, 1), (1, 0, 1) and (3, −1, 2) are not (since the third vector is the sum of the first two). Vectors which are not linearly independent are called linearly dependent.
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2 The projective space of linear dependences 3 Example I 4 Example II 5 Example III: (calculus required) 6 See also |
Let V be a vector space over a field K.
If v1, v2, ..., vn are elements of V, we say that they are linearly dependent over K if there exist elements a1, a2, ..., an in K not all equal to zero such that:
If there do not exist such field elements, then we say that v1, v2, ..., vn are linearly independent.
An infinite subset of V is said to linearly independent if all its finite subsets are linearly independent.
To focus the definition on linear independence, we can say that the vectors v1, v2, ..., vn are linearly independent, if and only if the following condition is satisfied:
Whenever a1, a2, ..., an are elements of K such that:
The concept of linear independence is important because a set of vectors which is linearly independent and spans some vector space, forms a basis for that vector space.
A linear dependence among vectors v1, ..., vn is a vector (a1, ..., an) with n scalar components, not all zero, such that
The vectors (1, 1) and (−3, 2) in R2 are linearly independent.
Proof:
Let a, b be two real numbers such that:
Let V=Rn and consider the following elements in V:
Proof:
Suppose that a1, a2,...,an are elements of Rn such that
Let V be the vector space of all functionss of a real variable t. Then the functions et and e2t in V are linearly independent.
Proof:
Suppose a and b are two real numbers such that
Subtracting the first relation from the second relation, we obtain:
From the first relation we then get:
Definition
or, more concisely:
(Note that the zero on the right is the zero element in V, not the zero element in K.)
then ai = 0 for i = 1, 2, ..., n.The projective space of linear dependences
If such a linear dependence exists, then the n vectors are linearly dependent. It makes sense to identify two linear dependences if one arises as a non-zero multiple of the other, because in this case the two describe the same linear relationship among the vectors. Under this identification, the set of all linear dependences among v1, ...., vn is a projective space.Example I
Then:
Solving for a and b, we find that a = 0 and b = 0.Example II
Then e1,e2,...,en are linearly independent.
Since
then ai = 0 for all i in {1, .., n}.Example III: (calculus required)
for all values of t. We need to show that a = 0 and b = 0. In order to do this, we differentiate both sides of (1) to get
which also holds for all values of t.
and, by plugging in t = 0, we get b = 0.
and again for t = 0 we find a = 0.
