How to evaluate the limit of a real-valued function Guide, Meaning , Facts, Information and Description
In mathematics, the definition of the limit of a function does not cover how to evaluate the limit of a real-valued function: it is not computational, on the face of it.
For "well-behaved" functions (i.e., continuous ones), the limit as x approaches c can be found by directly substituting c for x. For example, if f(x) = 7 as x approaches 32, the limit is 7 (the limit of a constant is a constant). Another example is f(x) = 2x - 5; in that situation, as x approaches 3, f(x) approaches f(3) = 2·3 - 5 = 1.
This is only a tool for this special case. Please note that the definition of limit doesn't involve the point f(c) at all. Its value can be arbitrary, or can even not exist, and the limit won't change. But if the function is continous around that point, the limit and the function value at that point happen to be the same.
Limits are more interesting when they are unreachable; for example: if f(x) = (x³ − 1) / (x − 1) then, x cannot be set equal to 1 (as that would result in division by zero). More formally, the value 1 is not in the function domain.
Here, however, f(x) does approach some number c as x approaches 1. One can compute f(0.9) = 2.71, f(0.99) = 2.9701, f(0.999) = 2.997001, f(1.1) = 3.31, f(1.01) = 3.0301, f(1.001) = 3.003001.
We see that, as x approaches 1, f(x) approaches 3; however, x is never equal to 1, and f(x) never equals 3. The limit can be verified using algebra. Since (x2 + x + 1)(x − 1) = (x3 − 1), g(x) = x2 + x + 1, g(x) = f(x) (for any x ≠ 1). g(x) and f(x) are identical at every point, except where x = 1; f(x) has a 'hole' in its domain at 1. Via direct substitution (x = 1) one can determine the limit of g(x) to be 12 + 1 + 1 = 3, which is the value f(x) approaches as it approaches the hole.
Here we have used the following rule:
if it so happens that if g(x) = f(x) for all values of x, except for c; then, so long as g(x) has a limit, that limit will be equal to the limit of f(x).
The above also shows that whether or not f(c) exists has no bearing on whether or not the limit of f(x) (as x approaches c) exists. Should f(c) exist, its value has no bearing on the limit.
Not every function has a limit at every point. Consider:
When trying to evaluate a limit by simply substitution c into the function, one often would have to divide by zero, which is, of course, impossible. Here l'Hôpital's rule helps: If f(c)->0, g(c)->0, and both derivatives f'(c) and g'(c) are defined, then:
The "squeeze theorem" (or "pinching theorem," as it is also known) is a theorem telling us that if three functions f(x), g(x) and h(x) are given such that h(x) ≤ f(x) ≤ g(x) and if the limit, L, (as x approaches c) of h(x) is equal to the limit (as x approaches c) of g(x), then the limit of f(x) not only exists, but is also equal to L. The function f(x) is "squeezed" between g(x) and '\'h(x'').
One might ask whether there is some relationship between |f(x) − L| (the absolute value [of the function, at x, minus its limit, L, as x approaches c]) and |x − c| (the absolute value [of x minus the number it is approaching]). For every number, ε > 0, there is some number, δ > 0; such that, if 0 < |x − c| < δ, then |f(x) − L| < ε. In other words, if the distance between x and c is less than δ, then the distance between f(x) and L is less than ε. The ε chosen may be made arbitrarily small. The above statement is one common definition of the limit of a real-valued function.
For example; the limit of (3x − 2), as x approaches 3, is 7; f(3) = 7. If one determines that the absolute value [of the function, at x, minus its limit (as x approaches 3)], should be less than 0.003 (that is, one is attempting to determine what value of x will generate an f(x) within 0.003 of the limit of f(x), as x approaches c = 3); then, one can write: |(3x − 2) - 7| = |3x − 9| = 3|x − 3| < 0.003. Noting that 0 < |x − c| < δ and that, in this situation, c = 3; we can write 0 < |x − 3| < δ and since 3|x − 3| < 0.003; it is only logical to conclude that |x − 3| < 0.003 / 3 = 0.001; and thus, any value within 0.001, of 3, will produce a value within 0.003 of f(x)'s limit (as x approaches 3); that is, a value within 0.003 of 7. For instance, f(3.001) = 7.003.
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Trigonometric rational function This is an Article on How to evaluate the limit of a real-valued function. Page Contains Information, Facts Details or Explanation Guide About How to evaluate the limit of a real-valued function Case of continuous functions
Limits not directly accessible
Limits do not always exist
L'Hôpital's rule, and division by zero
Three notable limits
The "squeeze theorem"
Approaching a limit
Exercises
1) See also
